简单搜索中坐标的遍历

    xiaoxiao2021-03-26  25

    八个方向:

    for (int dx = -1; dx <= 1; dx++) { for (int dy = -1; dy <= 1; dy++) { int nx = x + dx; int ny = y + dy; } }

    四个方向:

    int dx[4] = { 1,0,-1,0 }; int dy[4] = { 0,1,0,-1 }; for (int i = 0; i < 4; i++) { int nx = x + dx[i]; int ny = y + dy[i]; }

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