矩阵相乘

    xiaoxiao2022-06-23  17

    #include <iostream> using namespace std; int **getTranspose(int **list, int rows, int columns) { //创建一个newRow-newCol的转置矩阵 int newRow = columns, newCol = rows; int **trans = new int*[newRow]; for (int i = 0; i < newRow; i++) trans[i] = new int[newCol]; //进行转置 //按转置矩阵的行和列遍历 for (int i = 0; i < newRow; i++) { for (int j = 0; j < newCol; j++) trans[i][j] = list[j][i];//新矩阵的行元素 等于 原矩阵的列元素 } 或者按原矩阵的行和列循环遍历 //for (int i = 0; i < rows; i++) //{ // for (int j = 0; j < columns; j++) // trans[j][i] = list[i][j];//新矩阵的列元素 等于 原矩阵的行元素 //} return trans; } int** matrixMultiplication(int **m1, int **m2,int rows, int columns, int K)//新矩阵的行和列,以及K { //创建相乘之后的矩阵 int **multi = new int*[rows]; for (int i = 0; i < rows; i++) multi[i] = new int[columns]; //矩阵相乘,遍历新矩阵的行和列 for (int i = 0; i<rows; i++) { for (int j = 0; j<columns; j++) { int sum = 0; for (int k = 0; k < K; k++) sum += m1[i][k]*m2[k][j]; multi[i][j] = sum; } } return multi; } //输入 //2 3 //1 1 1 //1 2 1 //输出 //转置矩阵为: //1 1 //1 2 //1 1 //矩阵相乘结果为 //3 4 //4 6 int main() { //请输入矩阵的行和列 cout << "请输入矩阵的行和列:" << endl; int rows = 0, columns = 0; cin >> rows >> columns; cout << "请输入矩阵的各元素:" << endl; int **list = new int*[rows]; for (int i = 0; i < rows; i++) { list[i] = new int[columns]; for (int j = 0; j < columns; j++) cin >> list[i][j]; } for (int i = 0; i < rows; i++) { for (int j = 0; j < columns; j++) cout<< list[i][j]<<" "; cout << endl; } cout << "\n转置之后的矩阵为:" << endl; int ** transpose = getTranspose(list, rows, columns); for (int i = 0; i < columns; i++) { for (int j = 0; j < rows; j++) cout << transpose[i][j]<<" "; cout << endl; } cout << "\n相乘后的矩阵为:" << endl; int**multi = matrixMultiplication(list, transpose, rows, rows, columns); for (int i = 0; i < rows; i++) { for (int j = 0; j < rows; j++) cout << multi[i][j] << " "; cout << endl; } return 0; }
    转载请注明原文地址: https://ju.6miu.com/read-1123115.html

    最新回复(0)