Problem D: 社交网络
Time Limit: 2 Sec
Memory Limit: 128 MB
Submit: 223
Solved: 60
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Description
Input
Output
Sample Input
2 2 1 0 1 1 0 3 1 0 1 1 1 0 1 1 1 0
Sample Output
0.500
1.125
HINT
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <string>
#include <algorithm>
#include <vector>
#include <map>
using namespace std;
const int N = 100010;
typedef long long LL;
int vis[40][40], c[35][35];
int n, k;
int p[40];
int main()
{
memset(c,0,sizeof(c));
for(int i=0; i<=32; i++) c[i][0]=c[i][i]=1;
for(int i=1; i<=31; i++)
{
for(int j=1; j<i; j++)
{
c[i][j]=c[i-1][j]+c[i-1][j-1];
}
}
int t, x;
scanf("%d", &t);
while(t--)
{
memset(p,0,sizeof(p));
scanf("%d %d",&n, &k);
for(int i=1; i<=n; i++)
{
for(int j=1; j<=n; j++)
{
scanf("%d", &x);
p[i]+=x;
}
}
double sum=0;
for(int i=1; i<=n; i++)
for(int j=k;j<=p[i];j++)
sum=sum+(1.0*c[p[i]][j]/(1<<p[i]))/2;//统计一个人满足交际花条件的概率*1
printf("%.3f\n",sum);
}
return 0;
}
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