python 快速获取图片大小

    xiaoxiao2023-03-24  4

    实现原理

    利用header请求原则,只进行header请求获取图片info,有效缩短时间,减少图片下载解析的过程:

    url = "http://avatar.csdn.net/0/A/C/1_hi_chen_xingwang.jpg" rq = urllib2.Request(url,) rq.get_method = lambda:'HEAD' rp = urllib2.urlopen(rq,timeout= 10) msgs = rp.info().headers msg = rp.info() size = 0 # size = msgs.items()[0][1] for i in xrange(0,len(msgs)): pass head = msgs[i][:len('Content-Length')] # print head if str(head) == "Content-Length": pass size = msgs[i].split(':')[1] # print size else: pass print '------------------------------' print "--------->size<---------" image_size = int(size)/1024 print image_size
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