题目
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example: Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1 return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
思路
题目只要求返回true或者false,因此不需要记录路径。 由于只需要求出一个结果,因此,当左、右任意一棵子树求到了满意结果,都可以及时return。
代码
class Solution {
public:
bool hasPathSum(TreeNode
* root, int
sum) {
if(
!root)
return false;
if(
!root
->left
&& !root
->right)
return sum == root
->val;
return hasPathSum(root
->left,
sum-root->val)
||
hasPathSum(root
->right,
sum-root->val);
}
};
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