PAT-A 1002.A+B for Polynomials

    xiaoxiao2025-01-06  10

    1002. A+B for Polynomials

    This time, you are supposed to find A+B where A and B are two polynomials.

    Input

    Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, …, K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < … < N2 < N1 <=1000.

    Output

    For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

    Sample Input

    2 1 2.4 0 3.2 2 2 1.5 1 0.5

    Sample Output

    3 2 1.5 1 2.9 0 3.2

    程序代码:

    #include<stdio.h> #include<math.h> #define EPSION 0.1 double a[1001]={0}; int main() { int k; scanf("%d",&k); int i; double c; int e; for(i=0;i<k;i++) { scanf("%d%lf",&e,&c); a[e]=c; } scanf("%d",&k); for(i=0;i<k;i++) { scanf("%d%lf",&e,&c); a[e]+=c; } int count = 0; for(i=1000;i>=0;i--) { if(fabs(a[i])>=EPSION) count++; } if(count == 0) { printf("0"); return 0; } printf("%d ",count); for(i=1000;i>=0;i--) { if(fabs(a[i])>=EPSION) { printf("%d %.1f",i,a[i]); count--; if(count>0) putchar(' '); } } return 0; }
    转载请注明原文地址: https://ju.6miu.com/read-1295204.html
    最新回复(0)