php编程——验证码的实现(session方法)

    xiaoxiao2025-04-13  12

    php编程——验证码的实现(session方法)

    index.php(实现输入验证码页面)代码如下:

    <html> <head> <title>check code</title> </head> <body> <form name=check method=post action=check.php> <input type=hidden name=init value=1> 验证码:<input type=text name=code maxlength=4 style="width=50px;"> <!--得到验证码图片--> <img src=image.php> <p> <input type=submit value="提交"> </form> </body> </html>

    image.php(验证码生成页面)代码如下:

    <?php session_start(); srand((double)microtime()*1000000);  $authnum=rand(1000,9999); session_register("authnum"); header("content-type:image/png");         function creat_image($width,$height,$authnum)         {                 srand((double)microtime()*1000000);                  $im = imagecreate($width,$height);                  $black = ImageColorAllocate($im, 0,0,0);                  $white = ImageColorAllocate($im, 255,255,255);                  $gray = ImageColorAllocate($im, 200,200,200);                  imagefill($im,0,0,$gray);

                    //将四位整数验证码绘入图片                  imagestring($im, 5, 10, 3, $authnum, $black);                  for($i=0;$i<200;$i++)   //加入干扰象素                  {                              $randcolor = ImageColorallocate($im,rand(0,255),rand(0,255),rand(0,255));                     imagesetpixel($im, rand()%70 , rand()%30 , $randcolor);                  }                  ImagePNG($im);                  ImageDestroy($im);          } creat_image(60,20,$authnum); ?>

    check.php(验证界面)代码如下:

    <?php session_start();

    if(!isset($init)) $init=0; if($init) {  if($_POST['code']==$authnum)  {   echo "验证码正确!";  }

     else echo "验证码错误,请重新输入!"; } else echo "调用页面错误!" ?>

    转载请注明原文地址: https://ju.6miu.com/read-1298010.html
    最新回复(0)