LeetCode--No.232--Implement Queue using Stacks

    xiaoxiao2025-06-22  11

    Implement the following operations of a queue using stacks.

    push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- Get the front element.empty() -- Return whether the queue is empty. Notes: You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid.Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

    Subscribe to see which companies asked this question

    思路: 用两个栈来实现队列。先进先出变成先进后出,大概意思就是,把第一个栈里面的东西,都倒腾到第二个里面去,顺序反过来,就可以了。 具体还有一些细节可以优化。

    class MyQueue { // Push element x to the back of queue. Stack<Integer> tmp = new Stack<Integer>(); Stack<Integer> value = new Stack<Integer>(); public void push(int x) { if (!tmp.isEmpty()) tmp.push(x); else{ while(!value.isEmpty()) tmp.push(value.pop()); tmp.push(x); } } // Removes the element from in front of queue. public void pop() { if(value.isEmpty() && tmp.isEmpty()) return; if(!value.isEmpty()) value.pop(); else{ while(!tmp.isEmpty()) value.push(tmp.pop()); value.pop(); } } // Get the front element. public int peek() { if(value.isEmpty() && tmp.isEmpty()) return 0; if(!value.isEmpty()) return value.peek(); else{ while(!tmp.isEmpty()) value.push(tmp.pop()); return value.peek(); } } // Return whether the queue is empty. public boolean empty() { return tmp.isEmpty() && value.isEmpty(); } }

    转载请注明原文地址: https://ju.6miu.com/read-1300202.html
    最新回复(0)