Guess the number

Problem Description Happy new year to everybody! Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let (1) x % a = 0; (2) (x+1) % b = 0; (3) (x+2) % c = 0; and a, b, c are integers between 1 and 100. Given a,b,c, tell me what is the number of x ?   Input The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.   Output For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output "Impossible".   Sample Input 2 44 38 49 25 56 3   Sample Output Impossible 2575

题意：根据公式算出x的值。

#include<stdio.h> int main() { int t,a,b,c,i; scanf("%d",&t); while(t--) { scanf("%d%d%d",&a,&b,&c); int e=0; for(i=1000;i<=9999;i++) { if(i%a+(i+1)%b+(i+2)%c==0) { printf("%d\n",i); e=1; break; } } if(e==0) printf("Impossible\n"); } return 0; }