数据范围限制
找规律,分别看看出现在每一位上的1有什么规律
代码如下:
const w:array[1..11]of longint=(1,10,100,1000,10000,100000,1000000,10000000,100000000,1000000000,10000000000); p:array[1..11]of longint=(0,1,10,100,1000,10000,100000,1000000,10000000,100000000,1000000000); var a:array[1..11]of longint; n,k:longint; sum:int64; procedure init; var s:string; i:longint; begin readln(s); k:=length(s); for i:=1 to k do val(s[i],a[k-i+1]); val(s,n); end; procedure main; var i,j:longint; begin for i:=1 to k do sum:=sum+((n div w[i])*p[i]); for i:=2 to k do if a[i]>=2 then sum:=sum+p[i+1] else if a[i]=1 then sum:=sum+((n mod w[k])+1); if a[1]>=1 then write(sum+1) else write(sum); end; begin assign(input,'easygame.in'); reset(input); assign(output,'easygame.out'); rewrite(output); init; main; close(input); close(output); end.
