BZOJ2901 矩阵求和

    xiaoxiao2026-01-05  11

    这TM不就是个傻逼式子么为鸡毛我居然推了这么半天……

    前缀和优化下,加个读入优化,就搞过去了

    #include<iostream> #include<cstdlib> #include<cstdio> #include<cstring> #include<ctime> #include<cmath> #include<algorithm> #include<iomanip> #include<queue> #include<map> #include<bitset> #include<stack> #include<vector> #include<set> using namespace std; #define MAXN 2010 #define MAXM 1010 #define INF 1000000000 #define MOD 1000000007 #define ll long long #define eps 1e-8 int n,m; ll sa[MAXN][MAXN],sb[MAXN][MAXN]; int a[MAXN][MAXN],b[MAXN][MAXN]; char xB[1<<15],*xS=xB,*xT=xB; #define getc() (xS==xT&&(xT=(xS=xB)+fread(xB,1,1<<15,stdin),xS==xT)?0:*xS++) inline int read() { int x=0,f=1;char ch=getc(); while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getc();} while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getc();} return x*f; } int main(){ int i,j,x,y,xx,yy; n=read(); m=read(); for(i=1;i<=n;i++){ for(j=1;j<=n;j++){ a[i][j]=read(); sa[i][j]=sa[i-1][j]+a[i][j]; } } for(i=1;i<=n;i++){ for(j=1;j<=n;j++){ b[i][j]=read(); sb[i][j]=sb[i][j-1]+b[i][j]; } } while(m--){ x=read(); y=read(); xx=read(); yy=read(); if(x>xx){ swap(x,xx); } if(y>yy){ swap(y,yy); } ll ans=0; for(i=1;i<=n;i++){ ans+=(sa[xx][i]-sa[x-1][i])*(sb[i][yy]-sb[i][y-1]); } printf("%lld\n",ans); } return 0; } /* */

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