递归
不断与当前索引处元素交换,进入递归。
字典序
从尾端寻找第一个变小的数i,再从尾端寻找比他大于或等于最小数j,交换,将索引i后面数逆转。
#include <iostream>
#include <vector>
using namespace std;
#define N 4
void createPermutation(
vector<vector<int>> &res,
int &A,
int &n,
int &m,
int beg)
{
if (m < A)
{
vector<int> v = res[m-
1];
for (
int i = beg+
1;i <=n;++i)
{
createPermutation(res, A, n, m, beg +
1);
if (i == n)
break;
vector<int> v1{ v };
swap(v1[beg], v1[i]);
res[m++] = v1;
}
}
}
bool nextPermutation(
vector<int>::iterator beg,
vector<int>::iterator end)
{
if (beg == end)
return false;
auto itI = beg;
if ((++itI) == end)
return false;
auto itJ = end;
--itJ;
itI = itJ;
--itI;
for (;;--itI,--itJ)
{
if (*itI < *itJ)
{
auto itK = end;
while (*itI >= *(--itK));
iter_swap(itI, itK);
reverse(itJ, end);
return true;
}
if (itI == beg)
{
reverse(beg, end);
return false;
}
}
}
int main() {
vector<int> pos(N);
for (
int i =
0;i < N;++i)
{
pos[i] = i;
}
pos[
3] =
1;
int n = N, A =
1;
while (n !=
1)
{
A *= n;
--n;
}
n =
1;
cout <<
"字典序" << endl;
do
{
cout << n <<
":\t";
for (
const int &im : pos)
{
cout << im <<
"\t";
}
cout << endl;
++n;
}
while (nextPermutation(pos.begin(), pos.end()));
cout <<
"递归" << endl;
n =
1;
vector<vector<int>> res(A);
int m =
0;
res[m++] = pos;
n = N;
createPermutation(res, A, n, m,
0);
cout << N <<
"\t全排列\t" <<A<< endl;
n =
1;
for (
const auto &vm : res)
{
cout << n <<
":\t";
for (
const auto &im : vm)
{
cout << im <<
"\t";
}
cout << endl;
++n;
}
cout <<
"\t\t\t@zem" << endl;
system(
"pause");
return 0;
}
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