uva10763

    xiaoxiao2021-03-25  81

    题意:可以想象成数字的交换,然后最后判断是否有相换的数字是否有在换回来

    思路:如果匹配的話那麼兩邊的輸入排序後一定是一致的

    代碼:

    #include<cstdio> #include<algorithm> using namespace std; const int N = 500005; int n, n1[N], n2[N]; int main() { int i; while(scanf("%d", &n) && n) { bool flag = true; for(i=0; i<n; i++) { scanf("%d %d", &n1[i], &n2[i]); } if(n % 2 != 0) { flag = false; printf("NO\n"); continue; } sort(n1, n1+n); sort(n2, n2+n); for(i=0; i<n; i++) { if(n1[i] != n2[i]) { printf("NO\n"); flag = false; break; } } if(flag) printf("YES\n"); } return 0; }

    转载请注明原文地址: https://ju.6miu.com/read-13749.html

    最新回复(0)