简单的一个用定时器控制的流水灯c程序

用定时器以间隔500MS在6位数码管上依次显示0、1、2、3….C、D、E、F，重复。

#include<reg52.h> typedef unsigned int u8; typedef unsigned char u16; u8 code table[]={ 0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71}; u8 code weixuan[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf}; sbit duan=P2^6; sbit wei=P2^7; u8 i=0,j=0; void time0() {     TH0=(65536-5000)/256;  TL0=(65536-5000)%6;  EA=1;  ET0=1;  TR0=1;  while(1); } void main()  {   TMOD=0x01;   time0(); } void time1() interrupt 1 {   wei=0;  P0=weixuan[(i++)];    wei=1;   duan=0;    P0=table[(j++)%6];    duan=1;    TH0=(65536-5000)/256;  TL0=(65536-5000)%6; }