分析:感动~~好不容易遇见道水题。。
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<queue>
#define fo(i,a,b) for(int i=a;i<=b;i++)
#define fd(i,a,b) for(int i=a;i>=b;i--)
using namespace std;
int n;
typedef long long ll;
ll m;
const int N=
2e5+
6;
struct node
{
ll x,y;
}a[N];
bool cmp(node a,node b)
{
return a.x<b.x;
}
int main()
{
scanf(
"%d%lld",&n,&m);
fo(i,
1,n)
scanf(
"%lld%lld",&a[i].x,&a[i].y);
sort(a+
1,a+
1+n,cmp);
ll ans=
0;
fo(i,
1,n)
{
ll k=m/a[i].x;
if (k<a[i].y)
{
ans+=k;
break;
}
m-=a[i].x*a[i].y;
ans+=a[i].y;
}
printf(
"%lld\n",ans);
}
转载请注明原文地址: https://ju.6miu.com/read-17086.html