LeetCode-连续子数组的最大和

    xiaoxiao2021-03-25  101

    Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

    For example, given the array[−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray[4,−1,2,1]has the largest sum =6.

    click to show more practice.

    More practice:

    If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

    int maxSubArray(int A[], int n) { int curSum = 0; int maxSum = A[0]; for(int j = 0; j < n; j++) { if(curSum >= 0) { curSum += A[j]; } else { curSum = A[j]; } if(curSum > maxSum) { maxSum = curSum; } } return maxSum; }

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