JS递归调用定位ListView应该定位的项

继续上篇的定位问题，由于时间原因，上篇的定位不是很准确，下面将准确定位的JS代码共享出来： function getIndexFromLab(lab) { var arr = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] var j; for (j=0; j<arr.length; j++) { if (arr[j] === lab) break; } var i; for (i=0;i<list_model.count;i++) { if (list_model.get(i).sectionChar.substr(0, 1) === lab) { return i; } } if (i >= list_model.count) { return getIndexFromLab(arr[j-1]); } }以上JS代码，需要注意其递归调用处：return getIndexFromLab(arr[j-1]); 切记递归return，不熟悉递归的，这里可能会犯错。 调用定位处的代码如下： var idx = getIndexFromLab(modelData); list_view.positionViewAtIndex(idx, ListView.Beginning); 然后将Repeater的model补全如下： model: ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

这样，就能够根据鼠标选中分组准确定位ListView了。