leetcode 481. Magical Stringpython

    xiaoxiao2021-03-25  100

    A magical string S consists of only '1' and '2' and obeys the following rules:

    The string S is magical because concatenating the number of contiguous occurrences of characters '1' and '2' generates the string S itself.

    The first few elements of string S is the following: S = "1221121221221121122……"

    If we group the consecutive '1's and '2's in S, it will be:

    1 22 11 2 1 22 1 22 11 2 11 22 ......

    and the occurrences of '1's or '2's in each group are:

    1 2 2 1 1 2 1 2 2 1 2 2 ......

    You can see that the occurrence sequence above is the S itself.

    Given an integer N as input, return the number of '1's in the first N number in the magical string S.

    Note: N will not exceed 100,000.

    Example 1:

    Input: 6Output: 3Explanation: The first 6 elements of magical string S is "12211" and it contains three 1's, so return 3.

    class Solution(object): def magicalString(self, n): """ :type n: int :rtype: int """ S = [1,2,2] idx = 2 while len(S) < n: S += S[idx] * [(3 - S[-1])] idx += 1 return S[:n].count(1)

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