#include<iostream> using namespace std; //#pragma warning(disable:2162) class A{ }; //定义成员函数类型 typedef void (A::*F)(); //强制类型转换 #define Class_Func_Cast(selector) (F)(&selector) //#define str(selector) ##Class_Func_Cast(selector)## //#define str(a) #a //一定要共有继承,否则无法转换 class B:public A{ public: void f(){ cout << "B::f" << endl; } //测试this和成员函数的调用 void test(){ F f = Class_Func_Cast(B::f); (this->*f)(); cout << "B::test over" << endl; } //调用继承A的所有子类成员方法:void function(); static void callSonOfAClassVoidFunc(F f){ cout << "callSonOfAClassVoidFunc begin..." << endl; A a; (a.*f)(); cout << "callSonOfAClassVoidFunc end!" << endl; } }; class C:public A{ public: void f1(){ cout << "C::f" << endl; } void f2(){ cout << "C::f2" << endl; } void f3(){ cout << "C::f3" << endl; } //在B类(其他类)中调用C类(自己的类)本身的成员函数 void testf123(){ B::callSonOfAClassVoidFunc(Class_Func_Cast(C::f1)); B::callSonOfAClassVoidFunc(Class_Func_Cast(C::f2)); B::callSonOfAClassVoidFunc(Class_Func_Cast(C::f3)); cout << "C::test123 end!" << endl; } }; int main(){ //cout << str(B::f) << endl; cout << sizeof(F) << endl; B b; void (B::*f)() = &B::f; (b.*f)(); F f1 = Class_Func_Cast(B::f); (b.*f1)(); A a; (a.*f1)(); b.test(); //f1(); auto f2 = Class_Func_Cast(B::f); (a.*f2)(); C c; c.testf123(); cout << "func wrapper over" << endl; return 0; } 4 B::f B::f B::f B::f B::test over B::f callSonOfAClassVoidFunc begin... C::f callSonOfAClassVoidFunc end! callSonOfAClassVoidFunc begin... C::f2 callSonOfAClassVoidFunc end! callSonOfAClassVoidFunc begin... C::f3 callSonOfAClassVoidFunc end! C::test123 end! func wrapper over

参考:

编译器错误 C2064

Visual Studio 2010 其他版本 项不会计算为接受“number”个参数的函数

通过表达式调用了函数。 该表达式未计算为函数指针。

下面的示例生成 C2064：

// C2064.cpp int i, j; char* p; void func() { j = i(); // C2064, i is not a function p(); // C2064, p doesn't point to a function }

下面的示例生成 C2064：

// C2064b.cpp struct C { void func1(){} void func2(){} }; typedef void (C::*pFunc)(); int main() { C c; pFunc funcArray[2] = {&C::func1, &C::func2}; (funcArray[0])(); // C2064 }

可能的解决方法：

// C2064c.cpp struct C { void func1(){} void func2(){} }; typedef void (C::*pFunc)(); int main() { C c; pFunc funcArray[2] = {&C::func1, &C::func2}; (c.* funcArray[0])(); }

下面的示例生成 C2064：

// C2064d.cpp struct C { typedef void (C::*pFunc)(); pFunc funcArray[2]; void func1(){} void func2(){} C() { funcArray[0] = C::func1; funcArray[1] = C::func2; } void func3() { (funcArray[0])(); // C2064 } };

可能的解决方案：

// C2064e.cpp // compile with: /c struct C { typedef void (C::*pFunc)(); pFunc funcArray[2]; void func1(){} void func2(){} C() { funcArray[0] = &C::func1; funcArray[1] = &C::func2; } void func3() { (this->* funcArray[0])(); } };