Given a binary array, find the maximum number of consecutive 1s in this array. Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s.The maximum number of consecutive 1s is 3.
Note: The input array will only contain 0 and 1. The length of input array is a positive integer and will not exceed 10,000
public class MaxConsecutiveOnes {
public int findMaxConsecutiveOnes(
int[] nums) {
int res =
0;
int count =
0;
for(
int i=
0;i<nums.length;i++) {
if(nums[i]==
1) {
count++;
res = Math.max(res, count);
}
else {
count =
0;
}
}
return res;
}
}
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