题目描述:
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has the largest sum = 6.
解题思路:
我们首先设一个中间变量k,用它来记录子数组的和。当k加上下一元素的和小于该元素本身的值时,将其换成下一元素,否则,换成它们的和。最后将其中最大的k 值作为结果输出。
代码:
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int result = nums[0];
int k = nums[0];
for (int i = 1; i < nums.size(); i++) {
if (k + nums[i] < nums[i]) {
k = nums[i];
}
else {
k += nums[i];
}
if (k > result) {
result = k;
}
}
return result;
}
};
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