题目
Given a binary tree and a sum, find all root-to-leaf paths where each path’s sum equals the given sum.
For example: Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1 return [ [5,4,11,2], [5,8,4,5] ] 找出二叉树中所有和为sum的路径
思路
深度遍历
代码
class Solution {
public:
vector<vector<int> > ret;
void help(TreeNode *root,
vector<int> cur,
int target) {
cur.push_back(root->val);
if(!root->left && !root->right) {
if(root->val == target)
ret.push_back(cur);
return;
}
if(root->left)
help(root->left, cur, target-root->val);
if(root->right)
help(root->right, cur, target-root->val);
}
vector<vector<int> > pathSum(TreeNode* root,
int sum) {
if(!root)
return ret;
vector<int> temp;
help(root, temp, sum);
return ret;
}
};
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