MVC与webservice上传文件（图片和视频），希望帮且到一些朋友

最近做一个项目，要把图片和视频传到服务器上（网站与图片服务器分开），在网上找了好久，没找到完整的资料。

自己也折腾了半天，才把完整的代码实现完。可能好多朋友都有实现过，没分享代码吧，写得不好希望不要见笑！！

下面贴代码吧：首先MVC代码：

public string UploadVide() { string requesturl = ""; string result = "video/Videoitem/"; HttpFileCollectionBase fileToUpload = Request.Files; foreach (string file in fileToUpload) { var curFile = Request.Files[file]; Stream sr= curFile.InputStream; byte[] filebyt = new byte[curFile.ContentLength]; Stream fileStream = curFile.InputStream;//建立文件流对象 fileStream.Read(filebyt, 0, curFile.ContentLength); ServiceReference1.WebMp4serviceSoapClient sf = new ServiceReference1.WebMp4serviceSoapClient(); requesturl= sf.UpLoadStream(filebyt, curFile.FileName, "D:\\Video\\"); } // ServiceReference1.WebMp4serviceSoapClient sf = new ServiceReference1.WebMp4serviceSoapClient(); //sf.u return requesturl; }

其次：webservice代码：

[WebMethod] public string UpLoadStream(byte[] fs, string fileName, string requestPath) { try { string oldName = System.IO.Path.GetFileName(fileName); string expendName = System.IO.Path.GetExtension(oldName); string newName = DateTime.Now.ToString().Replace(" ", "").Replace(":", "").Replace("-", "").Replace("/", ""); ///定义并实例化一个内存流，以存放提交上来的字节数组 /// MemoryStream m = new MemoryStream(fs); ///定义实际文件对象，保存上载的文件。 FileStream f = new FileStream(requestPath + newName + expendName, FileMode.Create); ///把内内存里的数据写入物理文件 m.WriteTo(f); m.Close(); f.Close(); f = null; m = null; return requestPath + newName + expendName; } catch (Exception error) { } return ""; }

返回上传文件URL用于保存到数据库（根据你自己的需求来改）

html代码

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 < form  id="form1" action="/VideoAdmin/UploadVide" method="post" enctype="multipart/form-data">                      < table  cellspacing="0" cellpadding="0" border="0" class="tableadd">                          < tr >                              < td >                                  选择视频：                              </ td >                              < td >                                  < input  id="btnfile" type="file" name="file">< input  id="txturl" type="text" name="txturl"                                      value="D:" />< input  id="uploatvoide" type="submit" value="上传视频" />                              </ td >                          </ tr >                          < tr >                              < td >                                  视频名称                              </ td >                              < td >                                  < input  id="testvideoname" type="text" readonly="readonly" value="dddsds" />                              </ td >                          </ tr >                                               </ table >                      </ form >

 

代码经过测试，是可以的，希望帮到大家，写得不好，还希望不要见笑！