大数运算

#include<stdio.h> #include<string.h> int main() { int i,j; int num1[100],num2[100],num3[200]; int index; int over = 0;//over表示要仅为的数值 char str1[100],str2[100]; int temp; scanf("%s",str1); scanf("%s",str2); index = 0; for(i = strlen(str1) - 1;i >= 0;i --){ num1[index] = str1[i] - '0'; index ++; } printf("%d\n",strlen(str1)); index = 0; for(i = strlen(str2) - 1;i >= 0;i --){ num2[index] = str2[i] - '0'; index ++; } index = 0; while(index < strlen(str1) && index < strlen(str2)){ temp = num1[index] + num2[index] + over; num3[index] = temp % 10; over = temp / 10; index ++; } if(index == strlen(str1) && index < strlen(str2)){ for(j = index;j < strlen(str2);j ++){ num3[j] = (num2[j] + over) % 10; over = (num2[j] + over) / 10; index ++; } } if(index == strlen(str2) && index < strlen(str1)){ for(j = index;j < strlen(str1);j ++){ num3[j] = (num1[j] + over) % 10; over = (num1[j] + over) / 10; index ++; } } if(over){ num3[index] = over; index ++; } for(i = index - 1;i >= 0;i --) printf("%d",num3[i]); putchar('\n'); return 0; }