swift2 ，oc.上 for递减不能用了现在找到一下两个方法。
1.
for i in (0...10).reversed() {
print(i)
}
2.
for i in stride(from: 4, through: 0, by: -1) {
print(i)
}
Swift 的 stride 函数返回一个任意可变步长 类型值的序列. stride(from:3, to: 0, by:-1) [3,1) 步长是-1 from，through， stride(from:3, through: 0, by:-1) [3,0]
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