Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
class Solution {
public:
void merge(
vector<int>& nums1,
int m,
vector<int>& nums2,
int n) {
int i = m-
1, j = n-
1, k = m+n-
1;
while (j >=
0) {
nums1[k--] = i >=
0 && nums1[i] > nums2[j] ? nums1[i--] : nums2[j--];
}
}
};
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