# PAT甲级1028

xiaoxiao2021-03-26  11

# 1028. List Sorting (25)

时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input

Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1 3 1 000007 James 85 000010 Amy 90 000001 Zoe 60 Sample Output 1 000001 Zoe 60 000007 James 85 000010 Amy 90 Sample Input 2 4 2 000007 James 85 000010 Amy 90 000001 Zoe 60 000002 James 98 Sample Output 2 000010 Amy 90 000002 James 98 000007 James 85 000001 Zoe 60 Sample Input 3 4 3 000007 James 85 000010 Amy 90 000001 Zoe 60 000002 James 90 Sample Output 3 000001 Zoe 60 000007 James 85 000002 James 90 000010 Amy 90 #include<cstdio> #include<iostream> #include<string.h> #include<string> #include<vector> #include<algorithm> using namespace std; struct student { char ID[20], name[20]; int score; }; bool cmp1(student s1, student s2) { return strcmp(s1.ID, s2.ID)<=0; } bool cmp2(student s1, student s2) { if (strcmp(s1.name, s2.name)!=0) { if (strcmp(s1.name, s2.name) < 0) return true; else return false; } else return strcmp(s1.ID, s2.ID) <= 0;//比较器返回的是true或false，必须这样写 } bool cmp3(student s1, student s2) { if (s1.score != s2.score) return s1.score < s2.score; else return strcmp(s1.ID, s2.ID) <= 0; } int main() { int N, C; vector<student> v; student s; cin >> N >> C; for (int i = 0; i < N; i++) { //cin >> s.ID >> s.name >> s.score; scanf("%s %s %d", s.ID, s.name,&s.score); v.push_back(s); } switch (C) { case 1:sort(v.begin(), v.end(), cmp1); break; case 2:sort(v.begin(), v.end(), cmp2); break; case 3:sort(v.begin(), v.end(), cmp3); break; default: break; } for (int i = 0; i < v.size(); i++) { //cout << v[i].ID << " " << v[i].name << " " << v[i].score << endl; printf("%s %s %d\n", v[i].ID, v[i].name, v[i].score); } return 0; }

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