找到两个数的差为一个特定数

Given an integer 'k' and an sorted array A (can consist of both +ve/-ve nos), output 2 integers from A such that a-b=k.

void fun(vector<int> &a, int key) { int n = a.size(); if (n <= 1) { return; } key = abs(key); int p = 1; int q = 0; while (q < p && p < n) { if (a[p] - a[q] == key) { cout << a[p] << " " << a[q] << endl; return; } else if (a[p] - a[q] > key) { q++; } else { p++; } } }