首页
IT
登录
6mi
u
盘
搜
搜 索
IT
PAT-A1104
PAT-A1104
xiaoxiao
2021-03-25
147
#include<stdio.h> int main(){ int i, j, n; double ans=0,d[100010]={0}; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%lf",&d[i]); ans=ans+d[i]*i*(n-i+1); } printf("%0.2f\n",ans); return 0; }
转载请注明原文地址: https://ju.6miu.com/read-6129.html
技术
最新回复
(
0
)