给定输入字符串，将其整体转换为二进制
#include<math.h> #include<stdio.h> #include<stdlib.h> #include<string.h> #include<assert.h> #include<limits.h> #include<stdbool.h> using namespace std; char* fun233(char a) { int i = 0, t = 0; char res[1000]; char* pc; while (a != 0) { if (a % 2 == 0) res[i++] = '0'; else res[i++] = '1'; a = a / 2; } pc = (char*)malloc(i* sizeof(char)); for (int j = i - 1; j >= 0; --j) { pc[t++] = res[j]; } pc[t] = '\0'; return pc; } char* Decode(char* in) { int len = strlen(in); for (int i = 0; i < len; ++i) { if (i == 0) strcpy(in, fun233(in[i])); else strcat(in, fun233(in[i])); } return in; } int main() { char* in; char* res; in = (char*)malloc(512000 * sizeof(char)); scanf("\n%[^\n]", in); res = Decode(in); printf("%s\n", res); }