java 获取 请求路径

    xiaoxiao2021-03-25  171

    获取此次请求的URL

    String requestUrl = request.getScheme() //当前链接使用的协议 +"://" + request.getServerName()//服务器地址 + ":" + request.getServerPort() //端口号 + request.getContextPath() //应用名称,如果应用名称为 + request.getServletPath() //请求的相对url + "?" + request.getQueryString(); //请求参数 http://127.0.0.1:8080/world/index.jsp?name=lilei&sex=1 <Context path="world" docBase="/home/webapps" debug="0" reloadable="true"/> request.getScheme() = "http"; request.getServerName() = "127.0.0.1"; request.getServerPort() = "8080"; request.getContextPath() = "world"; request.getServletPath() = "index.jsp
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