Problem Description I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input 2 1 2 112233445566778899 998877665544332211
Sample Output Case 1: 1 + 2 = 3
Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110
Author Ignatius.L
代码
#include<stdio.h> #include<string.h> void high_accuracy(char *a,char *b){ int m,n,i=0,p=0; char c[1000001]; m=strlen(a)-1; n=strlen(b)-1; for(i=0;m>=0||n>=0;i++,m--,n--){ if(m>=0&&n>=0) c[i]=a[m]+b[n]-'0'+p; if(m>=0&&n<0) c[i]=a[m]+p; if(m<0&&n>=0) c[i]=b[n]+p; p=0; if(c[i]>'9') { c[i]=c[i]-10; p=1; } } if(p==1) printf("1"); while(i--){ printf("%c",c[i]); } } int main(){ char a[10000]={'\0'},b[10000]={'\0'}; int n=0,i=0; scanf("%d",&n); for(i=0;i<n;i++){ scanf("%s %s",a,b); printf("Case %d:\n",i+1); printf("%s + %s = ",a,b); high_accuracy(a,b); if(i<n-1) printf("\n\n"); else printf("\n"); } return 0; }