hdu 1020 Encoding

    xiaoxiao2021-03-26  25

    Encoding

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 43496    Accepted Submission(s): 19218 Problem Description Given a string containing only 'A' - 'Z', we could encode it using the following method:  1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string. 2. If the length of the sub-string is 1, '1' should be ignored.   Input The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.   Output For each test case, output the encoded string in a line.   Sample Input 2 ABC ABBCCC   Sample Output ABC A2B3C 题意是说假如输入“AABBAA” 应输入2A2B2A(坑在这) #include<iostream> #include<string> #include<math.h> #include<string.h> #include<stdio.h> #include<algorithm> #include<map> using namespace std; int main() { int num,j,k,i; cin>>num; while(num--) { string s1; int sum=0,k=0; cin>>s1; sum=0; for(i=1;i<=s1.size();i++) { if(s1[i]!=s1[i-1]) { sum=i-k+1-1; if(sum==1) cout<<s1[i-1]; else cout<<sum<<s1[i-1]; k=i; } } cout<<endl; } return 0; }
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