线段树背诵用模板

    xiaoxiao2021-03-26  33

    #include <cstdio> #define lson o<<1, l, m #define rson o<<1|1, m+1, r typedef long long LL; const int maxn = 100005; int n, a, b, c, k, q; LL sum[maxn<<2], add[maxn<<2], mul[maxn<<2], p; void up(int o) { sum[o] = (sum[o<<1]+sum[o<<1|1]) %p; } void build(int o, int l, int r) { add[o] = 0, mul[o] = 1; if(l == r) { scanf("%lld", &sum[o]); return; } int m = (l+r) >> 1; build(lson); build(rson); up(o); } void down(int o, int len) { // if(add[o] != 0 && mul[o] != 1) { add[o<<1] = (add[o<<1] * mul[o] + add[o]) %p; add[o<<1|1] = (add[o<<1|1] * mul[o] + add[o]) %p; mul[o<<1] = mul[o<<1] * mul[o] %p; mul[o<<1|1] = mul[o<<1|1] * mul[o] %p; sum[o<<1] = (sum[o<<1] * mul[o] + add[o] * (len-(len>>1))) %p; sum[o<<1|1] = (sum[o<<1|1] * mul[o] + add[o] * (len>>1)) %p; add[o] = 0, mul[o] = 1; // } } void update(int o, int l, int r, int op) { if(a <= l && r <= b) { if(op == 1) { add[o] = add[o]*c %p; mul[o] = mul[o]*c %p; sum[o] = sum[o]*c %p; } else { add[o] = (add[o] + c) %p; sum[o] = (sum[o] + (LL)c*(r-l+1)) %p; } return; } down(o, r-l+1); int m = (l+r) >> 1; if(a <= m) update(lson, op); if(m < b ) update(rson, op); up(o); } LL query(int o, int l, int r) { if(a <= l && r <= b) return sum[o] %p; down(o, r-l+1); int m = (l+r) >> 1; LL ans = 0; if(a <= m) ans = query(lson); if(m < b ) ans += query(rson); return ans %p; } int main() { scanf("%d%lld", &n, &q);scanf("%d", &p); build(1, 1, n); while(q--) { scanf("%d%d%d", &k, &a, &b); if(k != 3) { scanf("%d", &c); update(1, 1, n, k); } else printf("%lld\n", query(1, 1, n)); } return 0; }
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