1019. General Palindromic Number (20)

题目不难，用vector存储转换进制的各个位，然后转置一下，进行比较，相等即Yes

#include<iostream> #include<vector> using namespace std; int main() { int N;; int b; cin >> N >> b; char c; vector<int> vec1,vec2; while (N / b != 0) { vec1.push_back(N%b); N = N / b; } vec1.push_back(N); for (auto it = vec1.rbegin();it != vec1.rend();it++)//转置 vec2.push_back(*it); if (vec1 == vec2) cout << "Yes" << endl<<vec2[0];//判断 else cout << "No" << endl<<vec2[0]; for (unsigned int t = 1;t < vec2.size();t++) cout << " " << vec2[t]; cout << endl; }