题目描述
有一个n*m的棋盘(1<n,m<=400),在某个点上有一个马,要求你计算出马到达棋盘上任意一个点最少要走几步
输入输出格式
输入格式:一行四个数据,棋盘的大小和马的坐标
输出格式:一个n*m的矩阵,代表马到达某个点最少要走几步(左对齐,宽5格,不能到达则输出-1)
输入输出样例
输入样例#1:
3 3 1 1
输出样例#1:
0 3 2
3 -1 1
2 1 4
const
dx:array[1..8] of longint=(2,1,-1,-2,-2,-1,2,1);
dy:array[1..8] of longint=(-1,-2,-2,-1,1,2,1,2);
var
s:array[1..1000,1..1000] of longint;
a:array[1..10000,1..2] of longint;
bz:array[1..1000,1..1000] of boolean;
n,m,x,y,i,j,p:longint;
procedure aa(c,d:longint);
var
i,j,k,teal,word,x,y:longint;
begin
bz[c,d]:=false;
teal:=1; word:=1;
a[t,1]:=c; a[t,2]:=d;
s[c,d]:=1;
repeat
for i:=1 to 8 do
begin
x:=a[teal,1]+dx[i]; y:=a[t,2]+dy[i];
if (x>0)and(x<=n)and(y>0)and(y<=m)and bz[x,y] then
begin
inc(word);
a[word,1]:=x;
a[word,2]:=y;
bz[x,y]:=false;
s[x,y]:=s[a[teal,1],a[teal,2]]+1;
end;
end;
inc(teal);
until teal>word;
end;
begin
readln(n,m,x,y);
fillchar(s,sizeof(s),0);
fillchar(bz,sizeof(bz),true);
aa(x,y);
for i:=1 to n do
begin
for j:=1 to m do
begin
write(s[i,j]-1);
if (s[i,j]-1<10)and(s[i,j]-1>=0)then write(' ');
if ((s[i,j]-1<100)and(s[i,j]-1>=10))or(s[i,j]-1=-1) then write(' ');
if (s[i,j]-1<1000)and(s[i,j]-1>=100) then write(' ');
if s[i,j]-1>=1000 then write(' ');
end;
writeln;
end;
end.
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