Question: Given two strings s and t which consist of only lowercase letters.
String t is generated by random shuffling string s and then add one more letter at a random position.
Find the letter that was added in t.
Example:
Input: s = “abcd” t = “abcde”
Output: e
Explanation: ‘e’ is the letter that was added.
Top Solutions: 该解法利用两个字符串中所有字符的ASCII码总和相减，得出字符串t中多出来的一个字符的ASCII码。
public class Solution { public char findTheDifference(String s, String t) { // Initialize variables to store sum of ASCII codes for // each string int charCodeS = 0, charCodeT = 0; // Iterate through both strings and char codes for (int i = 0; i < s.length(); ++i) charCodeS += (int)s.charAt(i); for (int i = 0; i < t.length(); ++i) charCodeT += (int)t.charAt(i); // Return the difference between 2 strings as char return (char)(charCodeT - charCodeS); } }“Simple JAVA 8ms solution, 4 lines” https://discuss.leetcode.com/topic/56050/simple-java-8ms-solution-4-lines
My Solution:
