ionic2 APP退出事件

    xiaoxiao2021-04-12  38

    import {Component, ViewChild} from '@angular/core'; import {Platform, ToastController, Nav, IonicApp} from 'ionic-angular'; import {StatusBar, Splashscreen} from 'ionic-native'; import {TabsPage} from '../pages/tabs/tabs'; @Component({ templateUrl: 'app.html' }) export class MyApp { rootPage = TabsPage; backButtonPressed: boolean = false; //用于判断返回键是否触发 @ViewChild('myNav') nav: Nav; constructor(public ionicApp: IonicApp, public platform: Platform, public toastCtrl: ToastController) { platform.ready().then(() => { StatusBar.styleDefault(); Splashscreen.hide(); this.registerBackButtonAction();//注册返回按键事件 }); } registerBackButtonAction() { this.platform.registerBackButtonAction(() => { //如果想点击返回按钮隐藏toast或loading或Overlay就把下面加上 // this.ionicApp._toastPortal.getActive() || this.ionicApp._loadingPortal.getActive() || this.ionicApp._overlayPortal.getActive() let activePortal = this.ionicApp._modalPortal.getActive(); if (activePortal) { activePortal.dismiss().catch(() => {}); activePortal.onDidDismiss(() => {}); return; } let activeVC = this.nav.getActive(); let tabs = activeVC.instance.tabs; let activeNav = tabs.getSelected(); return activeNav.canGoBack() ? activeNav.pop() : this.showExit() }, 1); } //双击退出提示框 showExit() { if (this.backButtonPressed) { //当触发标志为true时,即2秒内双击返回按键则退出APP this.platform.exitApp(); } else { this.toastCtrl.create({ message: '再按一次退出应用', duration: 2000, position: 'top' }).present(); this.backButtonPressed = true; setTimeout(() => this.backButtonPressed = false, 2000);//2秒内没有再次点击返回则将触发标志标记为false }
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