PATB1012

A1  n==0 求和 A2  n%5==1 && n!=1求和 减去 n==1求和  A3  count（n%5==2） A4  avg(n%5==3) double 输出格式为%0.1d A4  max(n%5==4) #include <cstdio> #define MAXN 1000 int main() { int a[MAXN],n,i,a1=0,a3=0,a2=0,count2=0,count3=0,max=0,flag=1; double avg3=0; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%d",&a[i]);} for(i=1;i<=n;i++){ if(a[i]==0) a1=a1+a[i]; else if(a[i]%5==1){ if(flag%2==1){a2=a2+a[i];flag++;} else{a2=a2-a[i];flag++;}} else if(a[i]%5==2) count2++; else if(a[i]%5==3) {a3=a3+a[i];count3++;} else if(a[i]%5==4) if(a[i]>max) max=a[i];} avg3= a3/double(count3);//判断情况 if(a1) printf("%d ",a1); else printf("N "); if(a2!=0) printf("%d ",a2); else printf("N "); if(count2) printf("%d ",count2); else printf("N "); if(avg3) printf("%.1f ",avg3); else printf("N "); if(max) printf("%d",max); else printf("N"); 部分错误