Follow up for "Remove Duplicates": What if duplicates are allowed at most twice?
For example, Given sorted array nums = [1,1,1,2,2,3],
Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyond the new length.
class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int n = nums.size();
if(n <= 2)
return n;
vector<int> newArr(n);
int len = 2;
newArr[0] = nums[0];
newArr[1] = nums[1];
for(int i = 2; i < n; i++){
if(nums[i] == nums[i-1] && nums[i] == nums[i-2]){
continue;
}
else
newArr[len++] = nums[i];
}
swap(newArr, nums);
return len;
}
};
转载请注明原文地址: https://ju.6miu.com/read-670836.html