Leetcode 389（Java）

Total Accepted: 62128 Total Submissions: 120935 Difficulty: Easy Contributor: LeetCode Given two strings s and t which consist of only lowercase letters.

String t is generated by random shuffling string s and then add one more letter at a random position.

Find the letter that was added in t.

Example:

Input: s = “abcd” t = “abcde”

Output: e

Explanation: ‘e’ is the letter that was added.

因为只多加入了一个字母，所以两个字符串所有字母的ascII码值的差值转换为char类型即为对应的字母。 在这里要注意char类型与int类型的转换问题，AC码如下： public class Solution { public char findTheDifference(String s, String t) { int codeascii= (int)t.charAt(t.length()-1); for(int i=0;i<s.length();i++){ codeascii -= (int)s.charAt(i); codeascii += (int)t.charAt(i); } return (char)codeascii; } }