java泛型创建数组

    xiaoxiao2021-04-19  187

    在java中,不能通过直接通过T[] tarr=new T[10]的方式来创建数组,最简单的方式便是通过Array.newInstance(Class<t>type,int size)的方式来创建数组例如下面的程序。     public class ArrayMaker<T> {             private Class<T> type;                      public ArrayMaker(Class<T> type) {                 this.type = type;             }                      @SuppressWarnings("unchecked")             T[] createArray(int size) {                 return (T[]) Array.newInstance(type, size);             }                      List<T> createList() {                 return new ArrayList<T>();             }                      /**             * @param args             */             public static void main(String[] args) {                 /*                 * Even though kind is stored as Class<T> , erasure means that it is actually just being stored as a Class, with                 * no parameter. So, when you do some thing with it, as in creating an array, Array.newInstance( ) doesn’t                 * actually have the type information that’s implied in kind; so it cannot produce the specific result, wh ich                 * must therefore be cast, which produces a warning that you cannot satisfy.                 */                 ArrayMaker<Type> am2 = new ArrayMaker<Type>(Type.class);                 System.out.println(Arrays.asList(am2.createArray(10)));                 System.out.println(Arrays.asList(am2.createList()));             }                  }                  class Type {             @Override             public String toString() {                 return "type";             }         }    上面的这个例子比较简单,但是如果你有接触过泛型数组,你便对他的复杂度有一定的了解,由于创建泛型数组比较复杂,所以在实际的应用过程中一般会选择List的对泛型进行存储,如果实在需要使用泛型数组,则需要注意数组的在运行时的类型,think in java这本书中,对泛型数组的处理通过四个小程序对其进行了比较完整的描述。 程序一:这个程序主要说明了,在使用泛型数组中容易出现的问题,由于书中对于程序的说明比较详细,所以只对程序做引用。     class Generic<T> {         }                  public class ArrayofGeneric {             public static void main(String[] args) {                 Generic<Integer>[] genArr;                 /*                 * will throw ClassCastException :The problem is that arrays keep track of their actual type, and that type is                 * established at the point of creation of the array. So even though genArr has been cast to a Generic < Integer                 * >[] , that information only exists at compile time (and without the @SuppressWarnings annotation, you’d get a                 * warning for that cast). At run time, it’s still an array of Object, and that causes problems.                 */                 // genArr = (Generic<Integer>[]) new Object[] {};                 /* can not create a generic of array */                 // genArr=new Generic<Integer>[2];                 genArr = (Generic<Integer>[]) new Generic[2];                 System.out.println(genArr);             }         }   程序二:这个程序主要是说明在程序的执行过程中,泛型数组的类型信息会被擦除,且在运行的过程中数组的类型有且仅有Object[],如果我们强制转换成T[]类型的话,虽然在编译的时候不会有异常产生,但是运行时会有ClassCastException抛出。     /**         *          * Because of erasure, the runtime type of the array can only be Object[]. If we immediately cast it to T[], then at         * compile time the actual type of the array is lost, and the compiler may miss out on some potential error checks.         *          *          *          * archive $ProjectName: $         *          * @author Admin         *          * @version $Revision: $ $Name: $         */         public class ArrayOfGeneric2<T> {             public T[] ts;                      public ArrayOfGeneric2(int size) {                 ts = (T[]) new Object[size];             }                      public T get(int index) {                 return ts[index];             }                      public T[] rep() {                 return ts;             }                      public void set(int index, T t) {                 ts[index] = t;             }                      public static void main(String[] args) {                 ArrayOfGeneric2<String> aog2 = new ArrayOfGeneric2<String>(10);                 Object[] objs = aog2.rep();                 System.out.println(objs);                 /* will throw ClassCastException */                // String[] strs = aog2.rep();                 // System.out.println(strs);             }                  }    程序三:主要说明在对象中通过用Object[]来保存数据,则生成对象是,可以对其持有的对象在T和object之间进行转换,但是当设计到数组的转换时,还是会报ClassCastException     /**         *          * Initially, this doesn’t look very different compare with ArrayOfGeneric2.java , just that the cast has been moved.         * Without the ©SuppressWarnings annotations, you will still get "unchecked" warnings. However, the internal         * representation is now Object[] rather than T[]. When get( ) is called, it casts the object to T, which is in fact the         * correct type, so that is safe. However, if you call rep( ) , it again attempts to cast the Object[] to a T[], which         * is still incorrect, and produces a warning at compile time and an exception at run time. Thus there’s no way to         * subvert the type of the underlying array, which can only be Object[]. The advantage of treating array internally as         * Object[] instead of T[] is that it’s less likely that you’ll forget the runtime type of the array and accidentally         * introduce a bug (although the majority, and perhaps all, of such bugs would be rapidly detected at run time)         *          *          *          * archive $ProjectName: $         *          * @author Admin         *          * @version $Revision: $ $Name: $         */         public class ArrayOfGeneric3<T> {             Object[] ts;                      public ArrayOfGeneric3(int size) {                 ts = new Object[size];             }                      public T get(int index) {                 return (T) ts[index];             }                      public T[] rep() {                 return (T[]) ts;             }                      public void set(int index, T t) {                 ts[index] = t;             }                      public static void main(String[] args) {                 ArrayOfGeneric3<Integer> aog2 = new ArrayOfGeneric3<Integer>(10);                 Object[] objs = aog2.rep();                 for (int i = 0; i < 10; i++) {                     aog2.set(i, i);                     System.out.println(aog2.get(i));                 }                     Integer[] strs = aog2.rep();                     System.out.println(strs);             }         }    程序四:是对泛型数组相对而言比较完美的解决方案     /**         *          * The type token Class<T> is passed into the constructor in order to recover from the erasure, so that we can create         * the actual type of array that we need, although the warning from the cast must be suppressed with @SuppressWarnings.         * Once we do get the actual type, we can return it and get the desired results, as you see in main( ). The runtime type         * of the array is the exact type T[].         *          * @author Admin         *          * @version $Revision: $ $Name: $         */         public class ArrayOfGeneric4<T> {                      T[] ts;                      public ArrayOfGeneric4(Class<T> type, int size) {                 /* to solution array of generic key code! */                 ts = (T[]) Array.newInstance(type, size);             }                      public T get(int index) {                 return ts[index];             }                      public T[] rep() {                 return ts;             }                      public void set(int index, T t) {                 ts[index] = t;             }                      public static void main(String[] args) {                 ArrayOfGeneric4<Integer> aog2 = new ArrayOfGeneric4<Integer>(Integer.class, 10);                 Object[] objs = aog2.rep();                 for (int i = 0; i < 10; i++) {                     aog2.set(i, i);                     System.out.println(aog2.get(i));                 }                 try {                     Integer[] strs = aog2.rep();                     System.out.println("user Array.newInstance to create generci of array was successful!!!!! ");                 } catch (Exception ex) {                     ex.printStackTrace();                 }             }         }  
    转载请注明原文地址: https://ju.6miu.com/read-676223.html

    最新回复(0)