reeuests请求的超时时间和异常处理

    xiaoxiao2021-12-02  16

    import requests URL="https://api.github.com" def time_out_request():     try:         response=requests.get(URL,timeout=10)              except Exception,e:         print e.message          time_out_request()    
    转载请注明原文地址: https://ju.6miu.com/read-679675.html

    最新回复(0)