转自： http://blog.csdn.net/chenjinyu_tang/article/details/8136841
当函数的参数不确定时，可以使用*args 和**kwargs，*args 没有key值，**kwargs有key值。
[python] view plain copy print ? def fun_var_args(farg, *args): print "arg:", farg for value in args: print "another arg:", value fun_var_args(1, "two", 3) # *args可以当作可容纳多个变量组成的list result:
[python] view plain copy print ? arg: 1 another arg: two another arg: 3
**kwargs:
[python] view plain copy print ? def fun_var_kwargs(farg, **kwargs): print "arg:", farg for key in kwargs: print "another keyword arg: %s: %s" % (key, kwargs[key]) fun_var_kwargs(farg=1, myarg2="two", myarg3=3) # myarg2和myarg3被视为key， 感觉**kwargs可以当作容纳多个key和value的dictionaryresult:
[python] view plain copy print ? arg: 1 another keyword arg: myarg2: two another keyword arg: myarg3: 3 也可以用下面的形式：
[python] view plain copy print ? def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 args = ["two", 3] #list fun_var_args_call(1, *args) result：
[python] view plain copy print ? arg1: 1 arg2: two arg3: 3 [python] view plain copy print ? def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 kwargs = {"arg3": 3, "arg2": "two"} # dictionary fun_var_args_call(1, **kwargs) result：
[python] view plain copy print ? arg1: 1 arg2:"two" arg3:3
