Problem E: 平面上的点——Point类 (II)

    xiaoxiao2021-03-25  131

    Problem E: 平面上的点——Point类 (II)

    Time Limit: 1 Sec   Memory Limit: 4 MB Submit: 6791   Solved: 3440 [ Submit][ Status][ Web Board]

    Description

    在数学上,平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。

    根据“append.cc”,完成Point类的构造方法和show()方法,输出各Point对象的构造和析构次序。

    接口描述: Point::show()方法:按输出格式输出Point对象。

    Input

    输入多行,每行为一组坐标“x,y”,表示点的x坐标和y坐标,x和y的值都在double数据范围内。

    Output

    输出每个Point对象的构造和析构行为。对每个Point对象,调用show()方法输出其值:X坐标在前,Y坐标在后,Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。输出格式见sample。

    C语言的输入输出被禁用。

    Sample Input

    1,23,32,1

    Sample Output

    Point : (0, 0) is created.Point : (1, 2) is created.Point : (1, 2)Point : (1, 2) is erased.Point : (3, 3) is created.Point : (3, 3)Point : (3, 3) is erased.Point : (2, 1) is created.Point : (2, 1)Point : (2, 1) is erased.Point : (0, 0) is copied.Point : (1, 1) is created.Point : (0, 0)Point : (1, 1)Point : (0, 0)Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.

    HINT

    思考构造函数、拷贝构造函数、析构函数的调用时机。

    Append Code

    append.cc, #include<iostream> #include<iomanip> using namespace std; class Point{ private: double x; double y; public: Point():x(0),y(0){cout<<setprecision(16)<<"Point : (0, 0) is created."<<endl;} Point(double a,double b):x(a),y(b){cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is created."<<endl;} Point(double a):x(a),y(1){cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is created."<<endl;} void show(); Point(const Point &p) { x=p.x; y=p.y; cout<<setprecision(16)<<"Point : ("<<p.x<<", "<<p.y<<") is copied."<<endl; } ~Point() { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is erased."<<endl; } }; void Point::show() { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")"<<endl; } int main() { char c; double a, b; Point q; while(std::cin>>a>>c>>b) { Point p(a, b); p.show(); } Point q1(q), q2(1); q1.show(); q2.show(); q.show(); }
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