Problem G: 平面上的点和线——Point类、Line类 (III)

Problem G: 平面上的点和线——Point类、Line类 (III)

Time Limit: 1 Sec   Memory Limit: 128 MB Submit: 4761   Solved: 2207 [ Submit][ Status][ Web Board]

Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。 根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。 接口描述： Point::show()方法：按格式输出Point对象。 Line::show()方法：按格式输出Line对象。

Input

输入的第一行为N，表示后面有N行测试样例。每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。

Output

输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。 C语言的输入输出被禁用。

Sample Input

40,0 1,11,1 2,32,3 4,50,1 1,0

Sample Output

Point : (1, -2) is created.Point : (2, -1) is created.Point : (0, 0) is created.Point : (0, 0)=========================Point : (0, 0) is created.Point : (1, 1) is created.Line : (0, 0) to (1, 1) is created.Line : (0, 0) to (1, 1)Line : (0, 0) to (1, 1) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.=========================Point : (1, 1) is created.Point : (2, 3) is created.Line : (1, 1) to (2, 3) is created.Line : (1, 1) to (2, 3)Line : (1, 1) to (2, 3) is erased.Point : (2, 3) is erased.Point : (1, 1) is erased.=========================Point : (2, 3) is created.Point : (4, 5) is created.Line : (2, 3) to (4, 5) is created.Line : (2, 3) to (4, 5)Line : (2, 3) to (4, 5) is erased.Point : (4, 5) is erased.Point : (2, 3) is erased.=========================Point : (0, 1) is created.Point : (1, 0) is created.Line : (0, 1) to (1, 0) is created.Line : (0, 1) to (1, 0)Line : (0, 1) to (1, 0) is erased.Point : (1, 0) is erased.Point : (0, 1) is erased.=========================Point : (1, -2) is copied.Point : (2, -1) is copied.Line : (1, -2) to (2, -1) is created.Point : (1, -2) is copied.Point : (0, 0) is copied.Line : (1, -2) to (0, 0) is created.Point : (2, -1) is copied.Point : (0, 0) is copied.Line : (2, -1) to (0, 0) is created.Point : (0, 0) is copied.Point : (2, -1) is copied.Line : (0, 0) to (2, -1) is created.Line : (1, -2) to (2, -1)Line : (1, -2) to (0, 0)Line : (2, -1) to (0, 0)Line : (0, 0) to (2, -1)Line : (0, 0) to (2, -1) is erased.Point : (2, -1) is erased.Point : (0, 0) is erased.Line : (2, -1) to (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Line : (1, -2) to (0, 0) is erased.Point : (0, 0) is erased.Point : (1, -2) is erased.Line : (1, -2) to (2, -1) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.

HINT

Append Code

append.cc, #include <iostream> #include <iomanip> using namespace std; class Point { friend class Line; private: double x; double y; public: Point():x(0),y(0){cout<<"Point : ("<<x<<", "<<y<<") is created."<<endl;} Point(double xx,double yy):x(xx),y(yy) { cout<<"Point : ("<<x<<", "<<y<<") is created."<<endl; } Point(const Point &p):x(p.x),y(p.y) { cout<<"Point : ("<<x<<", "<<y<<") is copied."<<endl; } ~Point() { cout<<"Point : ("<<x<<", "<<y<<") is erased."<<endl; } void show() { cout<<"Point : ("<<x<<", "<<y<<")"<<endl; } }; class Line { friend class Point; private: Point p_1,p_2; public: Line(Point &m,Point &n):p_1(m),p_2(n) { cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is created."<<endl; } Line(double a,double b,double c,double d):p_1(a,b),p_2(c,d) { cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is created."<<endl; } ~Line() { cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is erased."<<endl; } void show() { cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<")"<<endl; } }; int main() { char c; int num, i; double x1, x2, y1, y2; Point p(1, -2), q(2, -1), t; t.show(); std::cin>>num; for(i = 1; i <= num; i++) { std::cout<<"=========================\n"; std::cin>>x1>>c>>y1>>x2>>c>>y2; Line line(x1, y1, x2, y2); line.show(); } std::cout<<"=========================\n"; Line l1(p, q), l2(p, t), l3(q, t), l4(t, q); l1.show(); l2.show(); l3.show(); l4.show(); }