Problem A: 好多书啊！

Problem A: 好多书啊！

Time Limit: 1 Sec   Memory Limit: 128 MB Submit: 373   Solved: 255 [ Submit][ Status][ Web Board]

Description

每次开学，都要买好多教材，好多好多的money就这样不见了，见了，了，......

我们以教材款的总额来表示我们的伤心度。所以！我们需要首先计算出我们花了多少钱！

定义一个类Book，拥有

1.数据成员name（string类型）和price（double类型）。

2.构造函数（含缺省构造函数）以及析构函数。它们都要输出一行文字，格式见样例（注意输出最后有换行哦）。

3. getName、getPrice、setName、setPrice四个方法，如何定义参照给出的main函数的调用方法。

Input

输入有3行，每行包括1个字符串（不含空白符）及一个实数，中间用1个空格隔开。

Output

呃~看样例吧。好复杂的！

Sample Input

C 10Data 20Char 30

Sample Output

A book C++ is created.A default book is created.A default book is created.A default book is created.The four books are: C++ C Data CharTheir total price is 102A book Char is erased.A book Data is erased.A book C is erased.A book C++ is erased.

HINT

Append Code

append.cc, #include <iostream> using namespace std; class Book{ private: string name; double price; public: Book() { cout << "A default book is created." << endl; } Book(string nn,double pp) { name=nn; price=pp; cout << "A book C++ is created."<<endl; } ~Book() { cout<<"A book "<<name<<" is erased."<<endl; } string getName(){ return name; } double getPrice(){ return price; } void setPrice(double pp){ price=pp; } void setName(string nnn){ name=nnn; } }; int main() { Book books[4]={Book("C++", 42.0)}; string tmp; double sum, price; int i; for (i = 0; i < 3; i++) { cin>>tmp>>price; books[i + 1].setName(tmp); books[i + 1].setPrice(price); } sum = 0; for (i = 0; i < 4; i++) { sum += books[i].getPrice(); } cout<<"The four books are: " << books[0].getName(); for (i = 1; i < 4; i++) { cout<<" "<<books[i].getName(); } cout<<endl<<"Their total price is "<<sum<<endl; return 0; }