链接
https://www.luogu.org/problem/show?pid=3637
题解
对边操作的LCT,把边化成点,然后操作。
这道题目从a到b和从b到a是不一样的,所以在reverse的时候要将权值乘-1。
代码
//LCT
#include <cstdio>
#include <algorithm>
#define maxn 500000
using namespace std;
int N, M, K, Q;
struct node
{
int rev, w, sum;
node *f, *ch[2];
}nd[maxn], *s[maxn];
inline int getwh(node *x)
{if(!x->f)return -1;if(x->f->ch[0]==x)return 0;if(x->f->ch[1]==x)return 1;return -1;}
inline bool isroot(node *x){return getwh(x)==-1;}
inline void join(node *x, node *y, int wh){if(x)x->f=y;if(y)y->ch[wh]=x;}
inline void rev(node *x){if(x)x->rev^=1;}
inline void pushdown(node *x)
{
if(!x)return;
if(x->rev)
{
x->w=-x->w;x->sum=-x->sum;swap(x->ch[0],x->ch[1]);
rev(x->ch[0]),rev(x->ch[1]);
x->rev=0;
}
}
inline void pushup(node *x)
{
pushdown(x->ch[0]),pushdown(x->ch[1]);
x->sum=x->w;
if(x->ch[0])x->sum+=x->ch[0]->sum;
if(x->ch[1])x->sum+=x->ch[1]->sum;
}
inline void rotate(node *x)
{
node *y=x->f, *z=y->f; int c=getwh(x);
if(isroot(y))x->f=y->f;else join(x,z,getwh(y));
join(x->ch[!c],y,c),join(y,x,!c);
pushup(y);pushup(x);
}
inline void splay(node *x)
{
node *y; int top=0;
for(y=x;!isroot(y);y=y->f)s[++top]=y;s[++top]=y;
for(;top;top--)pushdown(s[top]);
while(!isroot(x))
{
y=x->f;
if(isroot(y)){rotate(x);return;}
if(getwh(x)^getwh(y))rotate(x);else rotate(y);
rotate(x);
}
}
inline void access(node *x)
{
node *t=0;
while(x)
{
splay(x);
x->ch[1]=t;
pushup(x);
t=x,x=x->f;
}
}
inline void makeroot(node *x){access(x);splay(x);rev(x);}
inline void link(node *x, node *y){makeroot(x);x->f=y;}
inline void cut(node *x, node *y)
{
makeroot(x);access(y);splay(y);
if(y->ch[0]==x and !x->ch[1])x->f=y->ch[0]=0;
}
inline node* findroot(node *x)
{
while(x->f)x=x->f;
return x;
}
int main()
{
int a, b, c, i, t;
node *x, *y, *z;
scanf("%d%d%d%d",&N,&M,&K,&Q);
for(i=1;i<=M;i++)
{
scanf("%d%d%d",&a,&b,&c);
x=nd+N+i;
x->w=x->sum=c%K;
link(x,nd+a),link(x,nd+b);
}
for(i=1;i<=Q;i++)
{
scanf("%d%d%d",&t,&a,&b);
if(t==1)
{
scanf("%d",&c);
x=nd+N+M+i;
x->w=x->sum=c%K;
link(x,nd+a);link(x,nd+b);
}
if(t==2)
{
x=nd+a, y=nd+b;
makeroot(x), access(y), splay(y);
if(y->ch[0]!=x)z=y->ch[0];else z=x->ch[1];
if(!z)continue;
if(z->ch[0] or z->ch[1])continue;
cut(x,z),cut(y,z);
}
if(t==3)
{
scanf("%d",&c);
if(findroot(nd+a)!=findroot(nd+b)){printf("-1\n");continue;}
makeroot(nd+a),access(nd+b),splay(nd+b);
printf("%d\n",((nd[b].sum+c)%K+K)%K);
}
}
return 0;
}
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