没有什么好说的,求二叉树所有左叶子节点的值
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public int sumOfLeftLeaves(TreeNode root) { if (root == null) return 0; int sum = 0; if (root.left != null && root.left.left == null && root.left.right == null) { sum += root.left.val; } else { sum += sumOfLeftLeaves(root.left); } sum += sumOfLeftLeaves(root.right); return sum; } }
转载请注明原文地址: https://ju.6miu.com/read-9552.html