php的$

    xiaoxiao2021-12-14  19

    <div> <input type="text" placeholder="用户名" id="username" name="username"> </div> $name=$_POST['username']; $sql = "INSERT INTO `user` (`id`, `username`) VALUES (NULL, '$name')"; mysql_query($sql); $_POST['username']的取值为param.username,而不是input中的name的值

    传值方式:

    var param={ 'username':$("#userame").val()||'' } $.ajax({ url:"../php/register.manage.php", type:'POST', data:param, dataType:"JSON", success:function(result){ console.log(result); }, error:function(){ console.log("error"); } });

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